Hacker Rank Problem - Algorithm - Regex - IP Address Validation

IP Address Validation

The following is the solution to Hacker Rank problem IP Address Validation using Java.  For solutions to other Hacker Rank Problem visit my page HackerRank, alternatively try searching for the problem in my blog.

Score: 10/10

/**  *  */ package hackerRank; import java.util.Scanner; import java.util.regex.Matcher; import java.util.regex.Pattern; /**  * @author Arun.G  *  */ public class IPAddressValidation {        /**         * @param args         */        public static void main(String[] args) {               // TODO Auto-generated method stub             /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */         Scanner sc = new Scanner(System.in);         int n= sc.nextInt();         //Regex expression for Ipv4         String ip4Regex="^(25[0-5]|2[0-4][0-9]|1[0-9][0-9]|[0-9]{1,2})(\\.(25[0-5]|2[0-4][0-9]|1[0-9][0-9]|[0-9]{1,2})){3}$";         Pattern ip4Pattern = Pattern.compile(ip4Regex);         //Regex expression for Ipv6         String ip6Regex="^([0-9A-Fa-f]{1,4}:){7}[0-9A-Fa-f]{1,4}$";         Pattern ip6Pattern = Pattern.compile(ip6Regex);                     Matcher matcher;         for(int i=0;i<=n;i++)         {             String line = sc.nextLine();             if(!line.equals(""))             {                 matcher = ip4Pattern.matcher(line);                 //check if it is a Ipv4 Address                 if(matcher.matches())                     System.out.println("IPv4");                 else                 {                     matcher = ip6Pattern.matcher(line);                     //check if it is Ipv6 Address                     if(matcher.matches())                         System.out.println("IPv6");                     else //else it is neither                         System.out.println("Neither");                 }             }         }         //close the scanner         sc.close();        } }